What is the pressure gauge reading at the base of a tank filled to a depth of 1 ft.?

What is the pressure gauge reading at the base of a tank filled to a depth of 1 ft.?

• A. 0.233 psi
• B. 0.333 psi
• C. 0.433 psi
• D. 0.533 psi

Answer: (C)

To determine the pressure at the base of a tank filled with water to a depth of 1 foot, you can use the formula that relates pressure, depth, and the density of the fluid. The pressure at a certain depth in a fluid is given by the equation: \[ P = \rho \cdot g \cdot h \] Where: - \( P \) is the pressure at depth (in psi) - \( \rho \) is the density of the fluid (for water, it is approximately 62.4 lb/ft³) - \( g \) is the acceleration due to gravity (approximately 32.2 ft/s²) - \( h \) is the height of the fluid column (in feet) Using these values for water: - Density (\( \rho \)) = 62.4 lb/ft³ - Height (\( h \)) = 1 ft Substituting these into the formula gives: \[ P = \frac{62.4 \text{ lb/ft}^3 \times 1 \text{ ft}}{144} \] (where 144 is the conversion factor to convert from lb/ft² to psi) Calculating this gives: \[

To determine the pressure at the base of a tank filled with water to a depth of 1 foot, you can use the formula that relates pressure, depth, and the density of the fluid. The pressure at a certain depth in a fluid is given by the equation:

[ P = \rho \cdot g \cdot h ]

Where:

• ( P ) is the pressure at depth (in psi)

• ( \rho ) is the density of the fluid (for water, it is approximately 62.4 lb/ft³)

• ( g ) is the acceleration due to gravity (approximately 32.2 ft/s²)

• ( h ) is the height of the fluid column (in feet)

Using these values for water:

• Density (( \rho )) = 62.4 lb/ft³

• Height (( h )) = 1 ft

Substituting these into the formula gives:

[ P = \frac{62.4 \text{ lb/ft}^3 \times 1 \text{ ft}}{144} ]

(where 144 is the conversion factor to convert from lb/ft² to psi)

Calculating this gives:

[